A 0.16 pF parallel-plate capacitor is charged to 10 V.Then the battery is disconnected from the capacitor.When 1.00 * 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by:
A)(-5.0 V.)
B)(-1.1 V.)
C)0 V.
D)+1.1 V.
E)+5.0 V.

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The Answer of A 0.16 pF parallel-plate capacitor is charged to 10 V.Then the battery is disconnected from the capacitor.When 1.00 * 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by:
A)(-5.0 V.)
B)(-1.1 V.)
C)0 V.
D)+1.1 V.
E)+5.0 V.

A 016 PF Parallel-Plate Capacitor Is Charged to 10 V