The relationship for the current ration $\text { (I } \mathrm { I } _ { \mathrm { sec } } / \mathrm { I } \text { pri) }$ in a transformer is:
A) less than the turns ratio $\left( \mathrm { N } _ { \mathrm { sec } } / \mathrm { N } _ { \text {pri } } \right)$
B) the inverse of the turns ratio $\left( \mathrm { N } _ { \mathrm { sec } } / \mathrm { N } _ { \text {pri } } \right)$
C) more than the turns ratio $\left( \mathrm { N } _ { \mathrm { Sec } } / \mathrm { Npri } _ { \text {pri } } \right.$
D) the same as the turns ratio $\left( \mathrm { N } _ { \mathrm { sec } } / \mathrm { Np } _ { \mathrm { pri } } \right)$

Question

Quizplus · Accepted Answer

The current ratio is defined as the ratio of the secondary current to primary current, which is equal to the inverse of the turns ratio because the product of current and number of turns is constant in an ideal transformer. Thus, the correct relationship is I(sec)/I(pri) = N(pri)/N(sec).

The Relationship for the Current Ration (I Isec/I pri) \text { (I } \mathrm { I } _ { \mathrm { sec } } / \mathrm { I } \text { pri) } (I Isec​/I pri)

The Relationship for the Current Ration $\text { (I } \mathrm { I } _ { \mathrm { sec } } / \mathrm { I } \text { pri) }$