The relationship for the voltage ratio $\left( \mathrm { V } _ { \mathrm { sec } } / \mathrm { V } \text { pri } \right)$ in a transformer is:
A) the same as the turns ratio $\left(\mathrm{Nsec}/{\mathrm{Nspri}}\right)$
B) opposite to the turns ratio $\text { (Nsec/Npri) }$
C) more than the turns ratio $\left( \mathrm { N } _ { \mathrm { sec } } / \mathrm { N } _ { \mathrm { pri } } \right)$
D) less than the turns ratio $\left( N _ { \mathrm { sec } } / \mathrm { N } _ { \text {pri } } \right)$

Question

Quizplus · Accepted Answer

The relationship for the voltage ratio is the same as the turns ratio because the voltage induced in the secondary coil is directly proportional to the number of turns in the secondary coil and inversely proportional to the number of turns in the primary coil according to Faraday's law of electromagnetic induction. Therefore, the voltage ratio is equal to the turns ratio.

The Relationship for the Voltage Ratio (Vsec/V pri )\left( \mathrm { V } _ { \mathrm { sec } } / \mathrm { V } \text { pri } \right)(Vsec​/V pri )

The Relationship for the Voltage Ratio $\left( \mathrm { V } _ { \mathrm { sec } } / \mathrm { V } \text { pri } \right)$