Find the zeros of the function.
-$$f ( x ) = x ^ { 3 } + 12 x ^ { 2 } + 41 x + 42$$
A) $- 2 , - 3$, and $- 7$
B) 2,3 , and 7
C) $- 1 , - 3$, and $- 7$
D) $0,2,3$, and 7

Question

Quizplus · Accepted Answer

The zeros of the function can be found by factoring the cubic polynomial or using synthetic division. The correct zeros are $-2, -3$, and $-7$, which correspond to the roots of the equation $f(x) = 0$. This means when $x = -2, -3$, or $-7$, the function $f(x)$ equals zero.

Find the Zeros of the Function f(x)=x3+12x2+41x+42f ( x ) = x ^ { 3 } + 12 x ^ { 2 } + 41 x + 42f(x)=x3+12x2+41x+42

Find the Zeros of the Function $f ( x ) = x ^ { 3 } + 12 x ^ { 2 } + 41 x + 42$