Find the zeros of the function.
-$$f ( x ) = 9 x ^ { 2 } + 6 x - 8$$
A) 2 and $- 4$
B) $- \frac { 2 } { 3 }$ and $\frac { 4 } { 3 }$
C) $- 2$ and 4
D) $\frac { 2 } { 3 }$ and $- \frac { 4 } { 3 }$

Question

Quizplus · Accepted Answer

To find the zeros of the function $f(x) = 9x^2 + 6x - 8$, we can use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 9$, $b = 6$, and $c = -8$. Plugging these values into the formula gives $x = \frac{-6 \pm \sqrt{(6)^2 - 4(9)(-8)}}{2(9)}$, which simplifies to $x = \frac{-6 \pm \sqrt{36 + 288}}{18} = \frac{-6 \pm \sqrt{324}}{18} = \frac{-6 \pm 18}{18}$. This results in $x = \frac{2}{3}$ and $x = -\frac{4}{3}$, which corresponds to choice D.

Find the Zeros of the Function f(x)=9x2+6x−8f ( x ) = 9 x ^ { 2 } + 6 x - 8f(x)=9x2+6x−8

Find the Zeros of the Function $f ( x ) = 9 x ^ { 2 } + 6 x - 8$