Solve the problem.
-A building has a ramp to its front doors to accommodate the handicapped. If the distance from the building to the end of the ramp is 22 feet and the height from the ground to the front doors is 7 feet, how long is the ramp?
(Round to the nearest tenth.)
A) 5.4 ft
B) 20.9 ft
C) 23.1 ft
D) 9.9 ft

Question

Quizplus · Accepted Answer

The ramp, the height, and the distance from the building form a right triangle. Using the Pythagorean theorem: $c = \sqrt{a^2 + b^2}$, where $a = 22$ ft and $b = 7$ ft, the length of the ramp $c$ is $\sqrt{22^2 + 7^2} = \sqrt{484 + 49} = \sqrt{533} \approx 23.1$ ft.

Solve the Problem. -A Building Has a Ramp to Its Front Doors to Front