Solve.
-The equation $\theta _ { 2 } = \tan ^ { - 1 } ( \propto \mathrm { C } / \mathrm { G } )$ gives the phase angle of impedance in the parallel portion of a distributed constant circuit. Find $\theta _ { 2 }$ if $\omega = 130$ radians $/ \mathrm { sec } , \mathrm { C } = 0.01 \mu \mathrm { F } / \mathrm { km }$, and $\mathrm { G } = 1.45 \mu$ siemens/ $\mathrm { km }$.
A) $83.6 ^ { \circ }$
B) $40.1 ^ { \circ }$
C) $89.3 ^ { \circ }$
D) $0.7 ^ { \circ }$

Question

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The Answer of Solve.
-The equation $\theta _ { 2 } = \tan ^ { - 1 } ( \propto \mathrm { C } / \mathrm { G } )$ gives the phase angle of impedance in the parallel portion of a distributed constant circuit. Find $\theta _ { 2 }$ if $\omega = 130$ radians $/ \mathrm { sec } , \mathrm { C } = 0.01 \mu \mathrm { F } / \mathrm { km }$, and $\mathrm { G } = 1.45 \mu$ siemens/ $\mathrm { km }$.
A) $83.6 ^ { \circ }$
B) $40.1 ^ { \circ }$
C) $89.3 ^ { \circ }$
D) $0.7 ^ { \circ }$

Solve -The Equation θ2=tan⁡−1(∝C/G)\theta _ { 2 } = \tan ^ { - 1 } ( \propto \mathrm { C } / \mathrm { G } )θ2​=tan−1(∝C/G)

Solve
-The Equation $\theta _ { 2 } = \tan ^ { - 1 } ( \propto \mathrm { C } / \mathrm { G } )$