Find the partial fraction decomposition.
-$$\frac { - 7 } { x ( 3 x - 1 ) ( x + 1 ) } = \frac { A } { x } + \frac { B } { 3 x - 1 } + \frac { C } { x + 1 }$$
A) $\mathrm { A } = - 7 , \mathrm {~B} = \frac { 63 } { 4 } , \mathrm { C } = \frac { 7 } { 4 }$
B) $\mathrm { A } = 7 , \mathrm {~B} = \frac { 63 } { 4 } , \mathrm { C } = \frac { 7 } { 4 }$
C) $\mathrm { A } = 7 , \mathrm {~B} = - \frac { 63 } { 4 } , \mathrm { C } = - \frac { 7 } { 4 }$
D) $A = - 7 , B = - \frac { 63 } { 4 } , C = - \frac { 7 } { 4 }$

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The Answer of Find the partial fraction decomposition.
-$$\frac { - 7 } { x ( 3 x - 1 ) ( x + 1 ) } = \frac { A } { x } + \frac { B } { 3 x - 1 } + \frac { C } { x + 1 }$$
A) $\mathrm { A } = - 7 , \mathrm {~B} = \frac { 63 } { 4 } , \mathrm { C } = \frac { 7 } { 4 }$
B) $\mathrm { A } = 7 , \mathrm {~B} = \frac { 63 } { 4 } , \mathrm { C } = \frac { 7 } { 4 }$
C) $\mathrm { A } = 7 , \mathrm {~B} = - \frac { 63 } { 4 } , \mathrm { C } = - \frac { 7 } { 4 }$
D) $A = - 7 , B = - \frac { 63 } { 4 } , C = - \frac { 7 } { 4 }$

Find the Partial Fraction Decomposition −7x(3x−1)(x+1)=Ax+B3x−1+Cx+1\frac { - 7 } { x ( 3 x - 1 ) ( x + 1 ) } = \frac { A } { x } + \frac { B } { 3 x - 1 } + \frac { C } { x + 1 }x(3x−1)(x+1)−7​=xA​+3x−1B​+x+1C​

Find the Partial Fraction Decomposition $\frac { - 7 } { x ( 3 x - 1 ) ( x + 1 ) } = \frac { A } { x } + \frac { B } { 3 x - 1 } + \frac { C } { x + 1 }$