Gas in a container increases its pressure from 1 atm to 3 atm while keeping its volume constant. Find the work done (in J) by the gas if the volume is 5 liters. A) 0 B) 3 C) 5 D) 15 E) 15 × 10²

Question

Quizplus · Accepted Answer

Work done by a gas during a process is given by $W = P\Delta V$, where $P$ is the pressure and $\Delta V$ is the change in volume. Since the volume is kept constant ($\Delta V = 0$), the work done is 0 J, regardless of the pressure change.

Gas in a Container Increases Its Pressure from 1 Atm