Gas in a container expands at a constant pressure of 3 atm. Find the work done (in J) by the gas if the initial volume is 5 liters and the final volume is 10 liters.
A) 0
B) 150
C) 15
D) 1 500
E) 1.5

Question

Quizplus · Accepted Answer

Work done by gas = pressure x change in volume
Change in volume = final volume - initial volume = 10 L - 5 L = 5 L
Work done = 3 atm x 5 L = 15 L atm = 1500 J (since 1 L atm = 101.3 J)
Therefore, the answer is D) 1 500.

Gas in a Container Expands at a Constant Pressure of 3