Given: HCOOH + KOH$\rightarrow$HCOO⁻K⁺ + H₂O What mass of HCOO⁻K⁺is formed when 383 mL of 0.250 M HCOOH is mixed with 885 mL of 0.524 M KOH? A) 885 g B) 48.5 g C) 8.05 g D) 1.06 g E) 32.0 g

Question

Quizplus · Accepted Answer

The balanced chemical equation is:HCOOH + KOH → HCOO−K+ + H2OFrom the stoichiometry of the balanced equation, we can see that 1 mole of HCOOH reacts with 1 mole of KOH to produce 1 mole of HCOO−K+.The number of moles of HCOOH in 383 mL of 0.250 M HCOOH is:(0.383 L) × (0.250 mol/L) = 0.09575 molThe number of moles of KOH in 885 mL of 0.524 M KOH is:(0.885 L) × (0.524 mol/L) = 0.4639 molSince KOH is in excess, the number of moles of HCOO−K+ formed is equal to the number of moles of HCOOH, which is 0.09575 mol.The mass of HCOO−K+ formed is:(0.09575 mol) × (84.12 g/mol) = 8.05 gTherefore, the correct answer is C) 8.05 g.

Given: HCOOH + KOH →\rightarrow→ HCOO−K+ + H2O What Mass of HCOO−K+ is Formed When

Given: HCOOH + KOH $\rightarrow$ HCOO⁻K⁺ + H₂O What Mass of HCOO⁻K⁺is Formed When