In the equation given below, cyclopentanol (molar mass = 86.1 g/mol) reacts with pentanoic acid (molar mass = 102 g/mol) to produce cyclopentanoate(molar mass = 170.2 g/mol) and water. The volume of 0.297 M pentanoic acid needed for the complete reaction of 40.0 g cyclopentanol is _____ mL. A) 0.86 × 10³ B) 5.78 × 10³ C) 7.58 × 10³ D) 1.56 × 10³ E) 0.76 × 10³

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The Answer of In the equation given below, cyclopentanol (molar mass = 86.1 g/mol) reacts with pentanoic acid (molar mass = 102 g/mol) to produce cyclopentanoate(molar mass = 170.2 g/mol) and water. The volume of 0.297 M pentanoic acid needed for the complete reaction of 40.0 g cyclopentanol is _____ mL. A) 0.86 × 10³ B) 5.78 × 10³ C) 7.58 × 10³ D) 1.56 × 10³ E) 0.76 × 10³

In the Equation Given Below, Cyclopentanol (Molar Mass = 86