Answer the question.
-Focus groups of 12 people are randomly selected to discuss products of the Famous Company. It is determined that the mean number (per group) who recognize the Famous brand name is 7, and the standard deviation is
0)60. Would it be unusual to randomly select 12 people and find that greater than 10 recognize the Famous
Brand name?
A) Yes
B) No

Question

Quizplus · Accepted Answer

We can use the normal distribution to solve this problem since the sample size (n=12) is reasonably large. First, we need to calculate the standard error of the mean (SEM) which is calculated by dividing the standard deviation by the square root of the sample size:

SEM = 0.60 / sqrt(12) = 0.173

Next, we can calculate the z-score for 10 recognitions:

z = (10 - 7) / 0.173 = 17.34

Using a standard normal distribution table, we find that the probability of getting a z-score of 17.34 or higher (i.e. greater than 10 recognitions) is essentially zero (less than 0.0001). Therefore, it would be highly unusual to randomly select 12 people and find that greater than 10 recognize the Famous brand name.

Answer the Question. -Focus Groups of 12 People Are Randomly Selected to Discuss