Answer the question.
-Focus groups of 15 people are randomly selected to discuss products of the Yummy Company. It is determined that the mean number (per group) who recognize the Yummy brand name is 12.5, and the standard deviation is
0)58. Would it be unusual to randomly select 15 people and find that fewer than 9 recognize the Yummy brand
Name?
A) Yes
B) No

Question

Quizplus · Accepted Answer

To determine whether it would be unusual to randomly select 15 people and find that fewer than 9 recognize the Yummy brand name, we need to calculate the z-score and compare it to the normal distribution table.

z-score = (x - μ) / σ
where x = 9 (number of people who recognize the Yummy brand)
μ = 12.5 (mean number of people who recognize the Yummy brand)
σ = 0.58 (standard deviation)

z-score = (9 - 12.5) / 0.58 = -6.03

Looking at the normal distribution table, we can see that the probability of getting a z-score of -6.03 or lower is extremely low (less than 0.0001). This means that it would be very unusual to randomly select 15 people and find that fewer than 9 recognize the Yummy brand name. Therefore, the answer is A.

Answer the Question. -Focus Groups of 15 People Are Randomly Selected to Discuss