Solve Rational Equations with Variables in the Denominators
First, write the value(s)that make the denominator(s)zero. Then solve the equation.
-$$\frac { 6 } { 2 x - 2 } + \frac { 1 } { 2 } = \frac { 3 } { x - 1 }$$
A) $x \neq 1 ; \varnothing$
B) $x \neq 2 ; \{ 1 \}$
C) $\mathrm { x } \neq 1 ; \{ 1 \}$
D) $x \neq - 1,2 ; \{ 1,2 \}$

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The Answer of Solve Rational Equations with Variables in the Denominators
First, write the value(s)that make the denominator(s)zero. Then solve the equation.
-$$\frac { 6 } { 2 x - 2 } + \frac { 1 } { 2 } = \frac { 3 } { x - 1 }$$
A) $x \neq 1 ; \varnothing$
B) $x \neq 2 ; \{ 1 \}$
C) $\mathrm { x } \neq 1 ; \{ 1 \}$
D) $x \neq - 1,2 ; \{ 1,2 \}$

Solve Rational Equations with Variables in the Denominators First, Write 62x−2+12=3x−1\frac { 6 } { 2 x - 2 } + \frac { 1 } { 2 } = \frac { 3 } { x - 1 }2x−26​+21​=x−13​

Solve Rational Equations with Variables in the Denominators
First, Write $\frac { 6 } { 2 x - 2 } + \frac { 1 } { 2 } = \frac { 3 } { x - 1 }$