Solve Rational Equations with Variables in the Denominators
First, write the value(s)that make the denominator(s)zero. Then solve the equation.
-$$\frac { x - 6 } { 3 x } + 8 = \frac { x + 5 } { x }$$
A) $x \neq 0 ; \left\{ \frac { 21 } { 22 } \right\}$
B) $x \neq 0 ; \left\{ - \frac { 13 } { 2 } \right\}$
C) $x \neq 0,3 ; \left\{ \frac { 21 } { 22 } \right\}$
D) No restrictions; $\left\{ \frac { 11 } { 24 } \right\}$

Question

Quizplus · Accepted Answer

The denominators are $3x$ and $x$, so $x \neq 0$ to avoid division by zero. Solving the equation gives $x = \frac{21}{22}$.

Solve Rational Equations with Variables in the Denominators First, Write x−63x+8=x+5x\frac { x - 6 } { 3 x } + 8 = \frac { x + 5 } { x }3xx−6​+8=xx+5​

Solve Rational Equations with Variables in the Denominators
First, Write $\frac { x - 6 } { 3 x } + 8 = \frac { x + 5 } { x }$