Solve Rational Equations with Variables in the Denominators
First, write the value(s)that make the denominator(s)zero. Then solve the equation.
-$$\frac { 10 } { x } = \frac { 1 } { 2 x } + 38$$
A) $x \neq 0 ; \left\{ \frac { 1 } { 4 } \right\}$
B) $x \neq 0 ; \{ 4 \}$
C) $x \neq 0,2 ; \left\{ \frac { 21 } { 38 } \right\}$
D) No restrictions; $\{ 2 \}$

Question

Quizplus · Accepted Answer

The denominators $x$ and $2x$ become zero when $x = 0$, so $x \neq 0$ is a restriction. Solving the equation $\frac{10}{x} = \frac{1}{2x} + 38$ by finding a common denominator and simplifying leads to $x = \frac{1}{4}$.

Solve Rational Equations with Variables in the Denominators First, Write 10x=12x+38\frac { 10 } { x } = \frac { 1 } { 2 x } + 38x10​=2x1​+38

Solve Rational Equations with Variables in the Denominators
First, Write $\frac { 10 } { x } = \frac { 1 } { 2 x } + 38$