Find all values of x satisfying the given conditions.
-$y _ { 1 } = \frac { x + 6 } { 3 } , y _ { 2 } = \frac { x + 8 } { 6 }$, and $y _ { 1 } = y _ { 2 }$
A) $\{ - 4 \}$
B) $\{ 4 \}$
C) $\{ - 12 \}$
D) $\{ 3 \}$ Find all values of x such that y = 0.

Question

Quizplus · Accepted Answer

To find the value of $x$ that satisfies $y_1 = y_2$, set $\frac{x + 6}{3} = \frac{x + 8}{6}$ and solve for $x$. Multiplying both sides by 6 to eliminate the denominators gives $2(x + 6) = x + 8$. Simplifying, $2x + 12 = x + 8$, leads to $x = -4$.

Find All Values of X Satisfying the Given Conditions y1=x+63,y2=x+86y _ { 1 } = \frac { x + 6 } { 3 } , y _ { 2 } = \frac { x + 8 } { 6 }y1​=3x+6​,y2​=6x+8​

Find All Values of X Satisfying the Given Conditions $y _ { 1 } = \frac { x + 6 } { 3 } , y _ { 2 } = \frac { x + 8 } { 6 }$