Find the products AB and BA to determine whether B is the multiplicative inverse of A.
-$$A = \left[ \begin{array} { r r }
1 & 2 \
0 & - 6
\end{array} \right]$$
A)
$$\left[ \begin{array} { r r }
1 & \frac { 1 } { 3 } \
0 & - \frac { 1 } { 6 }
\end{array} \right]$$
B)
$\left[ \begin{array} { l } 1 - \frac { 1 } { 3 } \ 0 - \frac { 1 } { 6 } \end{array} \right]$
C)
$\left[ \begin{array} { r r } 0 & - \frac { 1 } { 6 } \ 1 & \frac { 1 } { 3 } \end{array} \right]$

D)

$\left[ \begin{array} { r r } - \frac { 1 } { 6 } & \frac { 1 } { 3 } \ 0 & 1 \end{array} \right]$

Question

Find the products AB and BA to determine whether B is the multiplicative inverse of A.
-$$A = \left[ \begin{array} { r r } 
1 & 2 \
0 & - 6
\end{array} \right]$$
A)
$$\left[ \begin{array} { r r } 
1 & \frac { 1 } { 3 } \
0 & - \frac { 1 } { 6 }
\end{array} \right]$$
B)
$\left[ \begin{array} { l } 1 - \frac { 1 } { 3 } \ 0 - \frac { 1 } { 6 } \end{array} \right]$
C)
$\left[ \begin{array} { r r } 0 & - \frac { 1 } { 6 } \ 1 & \frac { 1 } { 3 } \end{array} \right]$

D)

$\left[ \begin{array} { r r } - \frac { 1 } { 6 } & \frac { 1 } { 3 } \ 0 & 1 \end{array} \right]$

Quizplus · Accepted Answer

The correct answer is A because AB = BA = I, where I is the identity matrix.

Find the Products AB and BA to Determine Whether B A=[120−6]A = \left[ \begin{array} { r r } 1 & 2 \\0 & - 6\end{array} \right]A=[10​2−6​]

Find the Products AB and BA to Determine Whether B $A = \left[ \begin{array} { r r } 1 & 2 \\0 & - 6\end{array} \right]$