Solve the matrix equation for X.
-Let $\mathrm { A } = \left[ \begin{array} { r r } 1 & 3 \ - 1 & - 3 \end{array} \right]$ and $\mathrm { B } = \left[ \begin{array} { r r } - 1 & - 3 \ 1 & - 4 \end{array} \right] ; \quad \mathrm { X } + \mathrm { A } = \mathrm { B }$
A)
$X=\left[\begin{array}{rr}
-2 & -6 \
2 & -1
\end{array}\right]$

B)
$X = \left[ \begin{array} { r r } - 6 & - 2 \ - 1 & 2 \end{array} \right]$
C)
$X = \left[ \begin{array} { r r } 2 & - 1 \ - 2 & - 6 \end{array} \right]$
D)
$$X = \left[ \begin{array} { r r }
- 1 & - 2 \
- 6 & 2
\end{array} \right]$$

Question

Solve the matrix equation for X.
-Let $\mathrm { A } = \left[ \begin{array} { r r } 1 & 3 \ - 1 & - 3 \end{array} \right]$ and $\mathrm { B } = \left[ \begin{array} { r r } - 1 & - 3 \ 1 & - 4 \end{array} \right] ; \quad \mathrm { X } + \mathrm { A } = \mathrm { B }$
A)
$X=\left[\begin{array}{rr}
-2 & -6 \
2 & -1
\end{array}\right]$

B)
$X = \left[ \begin{array} { r r } - 6 & - 2 \ - 1 & 2 \end{array} \right]$
C)
$X = \left[ \begin{array} { r r } 2 & - 1 \ - 2 & - 6 \end{array} \right]$
D)
$$X = \left[ \begin{array} { r r } 
- 1 & - 2 \
- 6 & 2
\end{array} \right]$$

Quizplus · Accepted Answer

To solve for $X$ in the equation $X + A = B$, we subtract $A$ from both sides: $X = B - A$. Calculating $B - A$ gives us $\left[ \begin{array} { r r } -1-1 & -3-3 \ 1-(-1) & -4-(-3) \end{array} \right] = \left[ \begin{array} { r r } -2 & -6 \ 2 & -1 \end{array} \right]$.

Solve the Matrix Equation for X A=[13−1−3]\mathrm { A } = \left[ \begin{array} { r r } 1 & 3 \\ - 1 & - 3 \end{array} \right]A=[1−1​3−3​]

Solve the Matrix Equation for X $\mathrm { A } = \left[ \begin{array} { r r } 1 & 3 \\ - 1 & - 3 \end{array} \right]$