Solve the problem.
-When exposed to ethylene gas, green bananas will ripen at an accelerated rate. The number of days for ripening becomes shorter for longer exposure times. Assume that the table below gives average ripening times of
Bananas for several different ethylene exposure times. $$\begin{array} { l | l }
\begin{array} { l }
\text { Exposure timłRipening Time } \
\text { (minutes) }
\end{array} & \text { (days) } \
\hline 10 & 4.3 \
15 & 3.2 \
20 & 2.7 \
25 & 2.1 \
30 & 1.3
\end{array}$$ Plot the data and then find a line approximating the data. With the aid of this line, determine the rate of change of
Ripening time with respect to exposure time. Round your answer to two significant digits.
A) $- 0.14$ day per minute
B) 38 minutes
C) -6.7 davs per minute
D) $5.6$ davs

Question

Solve the problem.
-When exposed to ethylene gas, green bananas will ripen at an accelerated rate. The number of days for ripening becomes shorter for longer exposure times. Assume that the table below gives average ripening times of
Bananas for several different ethylene exposure times. $$\begin{array} { l | l } 
\begin{array} { l } 
\text { Exposure timłRipening Time } \
\text { (minutes) }
\end{array} & \text { (days) } \
\hline 10 & 4.3 \
15 & 3.2 \
20 & 2.7 \
25 & 2.1 \
30 & 1.3
\end{array}$$ Plot the data and then find a line approximating the data. With the aid of this line, determine the rate of change of
Ripening time with respect to exposure time. Round your answer to two significant digits.  
A) $- 0.14$ day per minute 
B) 38 minutes 
C) -6.7 davs per minute 
D) $5.6$ davs

Quizplus · Accepted Answer

Plotting the data and fitting a linear regression line gives:

Ripening time (days) = -0.14 * Exposure time (minutes) + 5.0

The slope of the line (-0.14) represents the rate of change of ripening time with respect to exposure time. Rounded to two significant digits, the answer is -0.14 day per minute.

Solve the Problem Plot the Data and Then Find a Line Approximating the Will