Evaluate the integral.
-$$\int _ { 0 } ^ { 1 / 9 } t ^ { 2 } d t$$
A) $- \frac { 1 } { 9 }$
B) $- \frac { 1 } { 2187 }$
C) 2187
D) $\frac { 1 } { 2187 }$

Question

Quizplus · Accepted Answer

$$\int _ { 0 } ^ { 1 / 9 } t ^ { 2 } d t=\frac{1}{3}t^3 \bigg|_0^{1/9}=\frac{1}{3}\left(\frac{1}{729}-0\right)=\frac{1}{3}\cdot\frac{1}{729}=\frac{1}{2187}$$ 
Therefore, the correct answer is D.

Evaluate the Integral ∫01/9t2dt\int _ { 0 } ^ { 1 / 9 } t ^ { 2 } d t∫01/9​t2dt

Evaluate the Integral $\int _ { 0 } ^ { 1 / 9 } t ^ { 2 } d t$