Solve the problem.
-Suppose that $h$ is continuous and that $\int _ { - 1 } ^ { 4 } \mathrm {~h} ( \mathrm { x } ) \mathrm { dx } = 2$ and $\int _ { 4 } ^ { 8 } \mathrm {~h} ( \mathrm { x } ) \mathrm { dx } = - 10$. Find $\int _ { - 1 } ^ { 8 } \mathrm {~h} ( \mathrm { t } ) \mathrm { dt }$ and $\int _ { 8 } ^ { - 1 } h ( t ) d t$.
A) $- 8 ; 8$
B) $8 ; - 8$
C) $- 12 ; 12$
D) $12 ; - 12$

Question

Quizplus · Accepted Answer

The integral from $-1$ to $8$ of $h(t) dt$ can be found by adding the integrals from $-1$ to $4$ and from $4$ to $8$, which gives $2 + (-10) = -8$. The integral from $8$ to $-1$ is the negative of the integral from $-1$ to $8$, hence $8$.

Solve the Problem hhh Is Continuous and That ∫−14 h(x)dx=2\int _ { - 1 } ^ { 4 } \mathrm {~h} ( \mathrm { x } ) \mathrm { dx } = 2∫−14​ h(x)dx=2

Solve the Problem $h$ Is Continuous and That $\int _ { - 1 } ^ { 4 } \mathrm {~h} ( \mathrm { x } ) \mathrm { dx } = 2$