Find the Center, Transverse Axis, Vertices, Foci, and Asymptotes of the Hyperbola

Find the center, transverse axis, vertices, foci, and asymptotes of the hyperbola.
- $$\frac { ( x + 4 ) ^ { 2 } } { 16 } - \frac { ( y + 3 ) ^ { 2 } } { 36 } = 1$$

A) center at $( - 4 , - 3 )$
transverse axis is parallel to $x$ -axis
vertices at $( - 10 , - 3 )$ and $( 2 , - 3 )$
foci at $( - 4 - 2 \sqrt { 13 } , - 3 )$ and $( - 4 + 2 \sqrt { 13 } , - 3 )$
asymptotes of $y + 3 = - \frac { 2 } { 3 } ( x + 4 )$ and $y + 3 = \frac { 2 } { 3 } ( x + 4 )$
B) center at $( - 4 , - 3 )$
transverse axis is parallel to $x$ -axis
vertices at $( - 8 , - 3 )$ and $( 0 , - 3 )$
foci at $( - 4 - 2 \sqrt { 13 } , - 3 )$ and $( - 4 + 2 \sqrt { 13 } , - 3 )$
asymptotes of $y + 3 = - \frac { 3 } { 2 } ( x + 4 )$ and $y + 3 = \frac { 3 } { 2 } ( x + 4 )$
C) center at $( - 3 , - 4 )$
transverse axis is parallel to $x$ -axis
vertices at $( - 7 , - 4 )$ and $( 1 , - 4 )$
foci at $( - 3 - 2 \sqrt { 13 } , - 4 )$ and $( - 3 + 2 \sqrt { 13 } , - 4 )$
asymptotes of $y + 4 = - \frac { 3 } { 2 } ( x + 3 )$ and $y + 4 = \frac { 3 } { 2 } ( x + 3 )$
D) center at $( - 4 , - 3 )$
transverse axis is parallel to $\mathrm { y }$ -axis
vertices at $( - 4 , - 7 )$ and $( - 4,1 )$
foci at $( - 4 , - 3 - 2 \sqrt { 13 } )$ and $( - 4 , - 3 + 2 \sqrt { 13 } )$
asymptotes of $y - 3 = - \frac { 2 } { 3 } ( x - 4 )$ and $y - 3 = \frac { 2 } { 3 } ( x - 4 )$