Convert the equation to the standard form for an ellipse by completing the square.
-$$16 x ^ { 2 } + 4 y ^ { 2 } + 32 x + 24 y - 12 = 0$$
A) $\frac { ( x + 3 ) ^ { 2 } } { 4 } + \frac { ( y + 1 ) ^ { 2 } } { 16 } = 1$
B) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$
C) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y - 3 ) ^ { 2 } } { 16 } = 1$
D) $\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$

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The Answer of Convert the equation to the standard form for an ellipse by completing the square.
-$$16 x ^ { 2 } + 4 y ^ { 2 } + 32 x + 24 y - 12 = 0$$
A) $\frac { ( x + 3 ) ^ { 2 } } { 4 } + \frac { ( y + 1 ) ^ { 2 } } { 16 } = 1$
B) $\frac { ( x + 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$
C) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y - 3 ) ^ { 2 } } { 16 } = 1$
D) $\frac { ( x + 1 ) ^ { 2 } } { 16 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$

Convert the Equation to the Standard Form for an Ellipse 16x2+4y2+32x+24y−12=016 x ^ { 2 } + 4 y ^ { 2 } + 32 x + 24 y - 12 = 016x2+4y2+32x+24y−12=0

Convert the Equation to the Standard Form for an Ellipse $16 x ^ { 2 } + 4 y ^ { 2 } + 32 x + 24 y - 12 = 0$