Convert the equation to the standard form for an ellipse by completing the square.
-$$4 x ^ { 2 } + 25 y ^ { 2 } - 8 x + 150 y + 129 = 0$$
A) $\frac { ( x + 3 ) ^ { 2 } } { 25 } + \frac { ( y - 1 ) ^ { 2 } } { 4 } = 1$
B) $\frac { ( x + 1 ) ^ { 2 } } { 25 } + \frac { ( y - 3 ) ^ { 2 } } { 4 } = 1$
C) $\frac { ( x - 1 ) ^ { 2 } } { 4 } + \frac { ( y + 3 ) ^ { 2 } } { 25 } = 1$
D) $\frac { ( x - 1 ) ^ { 2 } } { 25 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$

Question

Quizplus · Accepted Answer

The equation is converted to the standard form of an ellipse by completing the square for both x and y terms, resulting in the equation $\frac { ( x - 1 ) ^ { 2 } } { 25 } + \frac { ( y + 3 ) ^ { 2 } } { 4 } = 1$.

Convert the Equation to the Standard Form for an Ellipse 4x2+25y2−8x+150y+129=04 x ^ { 2 } + 25 y ^ { 2 } - 8 x + 150 y + 129 = 04x2+25y2−8x+150y+129=0

Convert the Equation to the Standard Form for an Ellipse $4 x ^ { 2 } + 25 y ^ { 2 } - 8 x + 150 y + 129 = 0$