Find an equation for the ellipse described.
-Focus at (-2, 0); vertices at (-8, 0)and (8, 0)
A) $\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 60 } = 1$
B) $\frac { x ^ { 2 } } { 60 } + \frac { y ^ { 2 } } { 64 } = 1$
C) $\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 64 } = 1$
D) $\frac { x ^ { 2 } } { 64 } + \frac { y ^ { 2 } } { 60 } = 1$

Question

Find an equation for the ellipse described.
-Focus at (-2, 0); vertices at (-8, 0)and (8, 0) 
A) $\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 60 } = 1$
B) $\frac { x ^ { 2 } } { 60 } + \frac { y ^ { 2 } } { 64 } = 1$
C) $\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 64 } = 1$
D) $\frac { x ^ { 2 } } { 64 } + \frac { y ^ { 2 } } { 60 } = 1$

Quizplus · Accepted Answer

The ellipse is horizontal with center at (0,0), vertices at (-8,0) and (8,0), so a=8. The distance from the center to the focus is c=2. Using c^2 = a^2 - b^2, we find b^2 = 60. Thus, the equation is $\frac { x ^ { 2 } } { 64 } + \frac { y ^ { 2 } } { 60 } = 1$.

Find an Equation for the Ellipse Described x24+y260=1\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 60 } = 14x2​+60y2​=1

Find an Equation for the Ellipse Described $\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 60 } = 1$