Determine algebraically whether the function is even, odd, or neither even nor odd.
-$f ( x ) = 3 \sqrt [ 3 ] { x }$
A) Even
B) Odd
C) Neither

Name: Determine algebraically whether the function is even, odd, or neither even nor odd. -$f ( x ) = 3 \sqrt [ 3 ] { x }$ A) Even B) Odd C) Neither
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Question

Quizplus · Accepted Answer

An odd function satisfies the condition $f(-x) = -f(x)$. For $f(x) = 3\sqrt[3]{x}$, substituting $-x$ for $x$ gives $f(-x) = 3\sqrt[3]{-x} = -3\sqrt[3]{x} = -f(x)$, which confirms that the function is odd.

Determine Algebraically Whether the Function Is Even, Odd, or Neither f(x)=3x3f ( x ) = 3 \sqrt [ 3 ] { x }f(x)=33x​

Determine Algebraically Whether the Function Is Even, Odd, or Neither $f ( x ) = 3 \sqrt [ 3 ] { x }$