Find an equation of variation for the given situation.
- y varies jointly as x and z and inversely as the product of w and p , and $y = \frac { 6 } { 5 }$ when x=1, z=6 , w=20 and p=8 .
A) $y = \frac { 32 x z } { w p }$
B) $y = \frac { 35 w p } { x z }$
C) y=52pwxz
D) $\mathrm { y } = \frac { 192 \mathrm { xz } } { \mathrm { wp } }$

Question

Find an equation of variation for the given situation.
- y varies jointly as  x and  z and inversely as the product of w and p , and $y = \frac { 6 } { 5 }$ when  x=1, z=6 ,  w=20  and  p=8 .
A) $y = \frac { 32 x z } { w p }$
B) $y = \frac { 35 w p } { x z }$
C)  y=52pwxz
D) $\mathrm { y } = \frac { 192 \mathrm { xz } } { \mathrm { wp } }$

Quizplus · Accepted Answer

y varies jointly as x and z and inversely as the product of w and p, so y = k(xz/wp). Substituting the given values, we get 6/5 = k(1*6/20*8). Solving for k, we get k = 32/5. Therefore, the equation of variation is y = (32/5)(xz/wp) = 32xz/(5wp).

Find an Equation of Variation for the Given Situation y=65y = \frac { 6 } { 5 }y=56​

Find an Equation of Variation for the Given Situation $y = \frac { 6 } { 5 }$