A parallel plate of area 400 cm² is dragged over a 0.20 cm thick layer of oil at a speed of 30.0 cm/s. It takes a force 1.20 N applied to the plate to sustain this speed. What is the viscosity of the oil? A)6.00 kg/(m∙s) B)20.0 kg/(m∙s) C)60.0 kg/(m∙s) D)0.200 kg/(m∙s) E)200 kg/(m∙s)

Question

Quizplus · Accepted Answer

The viscosity η can be calculated using the formula η = (F * d) / (A * v), where F is the force, d is the thickness of the oil layer, A is the area, and v is the velocity. Substituting the given values: η = (1.20 N * 0.002 m) / (0.04 m² * 0.30 m/s) = 0.200 kg/(m∙s).

A Parallel Plate of Area 400 Cm2 Is Dragged Over

A Parallel Plate of Area 400 Cm² Is Dragged Over