Solve the problem.
-A center-pivot irrigation system waters a sector-shaped field. Find the area of the field if the central angle, $\theta = 44 ^ { \circ }$ and the radius, $r = 148$ meters. Round to the nearest whole number.
A) $8411 \mathrm {~m} ^ { 2 }$
B) $16,821 \mathrm {~m} ^ { 2 }$
C) $57 \mathrm {~m} ^ { 2 }$
D) $114 \mathrm {~m} ^ { 2 }$

Question

Quizplus · Accepted Answer

The area of a sector of a circle is given by the formula $A = \frac{1}{2} r^2 \theta$ where $r$ is the radius and $\theta$ is the central angle in radians. First, convert the angle from degrees to radians: $\theta = 44^\circ = \frac{44}{180}\pi$ radians. Then, $A = \frac{1}{2} \times 148^2 \times \frac{44}{180}\pi \approx 8411 \mathrm{m}^2$.

Solve the Problem θ=44∘\theta = 44 ^ { \circ }θ=44∘ And the Radius

Solve the Problem $\theta = 44 ^ { \circ }$ And the Radius