Solve the Problem $\theta$ Of the Sun in the Sky at Any Latitude

Solve the problem.
-The angle of elevation $\theta$ of the sun in the sky at any latitude $L$ is calculated with the formula $\sin \theta = \cos \mathrm { D } \cos \mathrm { L } \cos \omega + \sin \mathrm { D } \sin \mathrm { L }$ . $\omega$ is the number of radians that the Earth has rotated through since noon when $\omega = 0$ . D is the declination of the sun. Westville has latitude $L = 36.5 ^ { \circ }$ . Find the angle of elevation $\theta$ in degrees of the sun at 3 PM on February 29, 2012, where at that time $\mathrm { D } \approx - 0.1425$ and $\omega \approx 0.7854$ .

A) $9.8 ^ { \circ }$
B) $0.5 ^ { \circ }$
C) $28.6 ^ { \circ }$
D) $27.4 ^ { \circ }$