Use the given values of n and p to find the minimum usual value µ - 2? and the maximum usual value µ + 2?
-n = 189, p = 0.13
A)Minimum: 15.32; maximum: 33.82
B)Minimum: 19.95; maximum: 29.19
C)Minimum: -18.18; maximum: 67.32
D)Minimum: 33.82; maximum: 15.32

Question

Quizplus · Accepted Answer

For a binomial distribution, the mean (µ) is given by n*p and the standard deviation (σ) is given by sqrt(n*p*(1-p)). Here, n = 189 and p = 0.13, so µ = 189*0.13 = 24.57 and σ = sqrt(189*0.13*(1-0.13)) ≈ 4.625. The minimum usual value is µ - 2σ = 24.57 - 2*4.625 = 15.32, and the maximum usual value is µ + 2σ = 24.57 + 2*4.625 = 33.82.

Use the Given Values of N and P to Find