Use the given values of n and p to find the minimum usual value µ - 2? and the maximum usual value µ + 2?
-n = 94, p = 0.20
A)Minimum: 11.04; maximum: 26.56
B)Minimum: 14.92; maximum: 22.68
C)Minimum: 26.56; maximum: 11.04
D)Minimum: -11.28; maximum: 48.88

Question

Quizplus · Accepted Answer

The mean µ is calculated as n * p = 94 * 0.20 = 18.8. The standard deviation ? is sqrt(n * p * (1-p)) = sqrt(94 * 0.20 * 0.80) = 3.88. Therefore, the minimum usual value is µ - 2? = 18.8 - 2(3.88) = 11.04, and the maximum usual value is µ + 2? = 18.8 + 2(3.88) = 26.56.

Use the Given Values of N and P to Find