If $f ( x ) = 10 x + 7$ and $g ( x ) = x ^ { 2 } - 3 x$, find $\left( \frac { f } { g } \right) ( x )$
A) $\left( \frac { f } { g } \right) ( x ) = \frac { 10 } { x } + \frac { 7 } { 3 x } , x \neq 0$
B) $\left( \frac { f } { g } \right) ( x ) = \frac { 10 x + 7 } { x ^ { 2 } - 3 x } , x \neq 0 , x \neq 3$
C) $\left( \frac { f } { g } \right) ( x ) = \frac { 10 } { x } - \frac { 7 } { 3 x } , x \neq 0$
D) $\left( \frac { f } { g } \right) ( x ) = \frac { 17 } { x - 3 } , x \neq 3$

Question

Quizplus · Accepted Answer

The Answer is B

If f(x)=10x+7f ( x ) = 10 x + 7f(x)=10x+7 And g(x)=x2−3xg ( x ) = x ^ { 2 } - 3 xg(x)=x2−3x

If $f ( x ) = 10 x + 7$ And $g ( x ) = x ^ { 2 } - 3 x$