Solve by completing the square.
-$$x ^ { 2 } = 3 - 8 x$$
A) $- 4 \pm 2 \sqrt { 19 }$
B) $- 1 \pm \sqrt { 19 }$
C) $- 4 \pm \sqrt { 19 }$
D) $4 + \sqrt { 19 }$

Question

Quizplus · Accepted Answer

To complete the square, rewrite the equation as $x^2 + 8x = 3$. Add $(8/2)^2 = 16$ to both sides to get $x^2 + 8x + 16 = 19$. This becomes $(x + 4)^2 = 19$. Solving for $x$, we get $x + 4 = \pm \sqrt{19}$, so $x = -4 \pm \sqrt{19}$.

Solve by Completing the Square x2=3−8xx ^ { 2 } = 3 - 8 xx2=3−8x

Solve by Completing the Square $x ^ { 2 } = 3 - 8 x$