Solve the equation by completing the square.
-$$7 x ^ { 2 } + 2 x - 5 = 0$$
A) $\frac { 7 } { 5 } , 1$
B) $\frac { 7 } { 5 } , - 1$
C) $\frac { 7 } { 5 } , 0$
D) $\frac { 5 } { 7 } , - 1$

Question

Quizplus · Accepted Answer

To complete the square, rewrite the equation as $7(x^2 + \frac{2}{7}x) = 5$. Then, add and subtract $(\frac{1}{7})^2$ inside the bracket: $7((x + \frac{1}{7})^2 - \frac{1}{49}) = 5$. Simplify and solve for $x$ to find the roots $\frac{5}{7}$ and $-1$.

Solve the Equation by Completing the Square 7x2+2x−5=07 x ^ { 2 } + 2 x - 5 = 07x2+2x−5=0

Solve the Equation by Completing the Square $7 x ^ { 2 } + 2 x - 5 = 0$