Factor.
-$8 \mathrm { c } ^ { 3 } + 125$
A) $( 2 c + 5 ) \left( 4 c ^ { 2 } - 10 c + 25 \right)$
B) $( 2 c - 5 ) \left( 4 c ^ { 2 } + 10 c + 25 \right)$
C) $( 2 c + 5 ) \left( 4 c ^ { 2 } + 25 \right)$
D) $( 8 c + 5 ) \left( c ^ { 2 } - 10 c + 25 \right)$

Question

Quizplus · Accepted Answer

This is a sum of cubes factorization, where $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$. Here, $8c^3 = (2c)^3$ and $125 = 5^3$, so the factorization is $(2c + 5)(4c^2 - 10c + 25)$.

Factor - 8c3+1258 \mathrm { c } ^ { 3 } + 1258c3+125

Factor
- $8 \mathrm { c } ^ { 3 } + 125$