Factor completely.
-$50 a ^ { 4 } b - 72 b ^ { 3 }$
A) $2 b ( 5 a - 6 b ) ^ { 2 }$
B) $2 b \left( 5 a ^ { 2 } + 6 b \right) \left( 5 a ^ { 2 } - 6 b \right)$
C) $2 b ( 5 a + 6 b ) ^ { 2 }$
D) Prime

Question

Quizplus · Accepted Answer

The greatest common factor (GCF) of $50a^4b$ and $72b^3$ is $2b$. Factoring out $2b$, we get $2b(25a^4 - 36b^2)$. Recognizing $25a^4 - 36b^2$ as a difference of squares, it can be factored further into $(5a^2)^2 - (6b)^2$, which gives $2b(5a^2 + 6b)(5a^2 - 6b)$.

Factor Completely 50a4b−72b350 a ^ { 4 } b - 72 b ^ { 3 }50a4b−72b3

Factor Completely $50 a ^ { 4 } b - 72 b ^ { 3 }$