Solve the equation.
-$\log _ { 12 } \left( x ^ { 2 } - x \right) = 1$
A) $- 3,4$
B) 1,12
C) $- 3 , - 4$
D) 3,4

Question

Quizplus · Accepted Answer

To solve the equation $\log _ { 12 } \left( x ^ { 2 } - x \right) = 1$, we first convert the logarithmic equation to its exponential form: $12^1 = x^2 - x$. This simplifies to $12 = x^2 - x$. Rearranging the equation gives $x^2 - x - 12 = 0$. Factoring this quadratic equation, we get $(x-4)(x+3) = 0$, which has the solutions $x = 4$ and $x = -3$.

Solve the Equation log⁡12(x2−x)=1\log _ { 12 } \left( x ^ { 2 } - x \right) = 1log12​(x2−x)=1

Solve the Equation $\log _ { 12 } \left( x ^ { 2 } - x \right) = 1$