Solve the equation.
-$\log _ { 8 } x ^ { 2 } = \log _ { 8 } ( 3 x + 28 )$
A) 7
B) $\frac { 7 } { 8 }$
C) $7 , - 4$
D) $\varnothing$

Name: Solve the equation. -$\log _ { 8 } x ^ { 2 } = \log _ { 8 } ( 3 x + 28 )$ A) 7 B) $\frac { 7 } { 8 }$ C) $7 , - 4$ D) $\varnothing$
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Question

Quizplus · Accepted Answer

Since the bases of the logarithms are the same, we can set the arguments equal to each other: $x^2 = 3x + 28$. Rearranging gives $x^2 - 3x - 28 = 0$, which factors to $(x-7)(x+4) = 0$. Thus, $x = 7$ or $x = -4$.

Solve the Equation log⁡8x2=log⁡8(3x+28)\log _ { 8 } x ^ { 2 } = \log _ { 8 } ( 3 x + 28 )log8​x2=log8​(3x+28)

Solve the Equation $\log _ { 8 } x ^ { 2 } = \log _ { 8 } ( 3 x + 28 )$