Find the center and the radius of the circle.
-$x ^ { 2 } + y ^ { 2 } + 10 x + 12 y + 61 = 9$
A) center $( - 6 , - 5 )$, radius $= 3$
B) center $( 5,6 )$, radius $= 9$
C) center $( - 5 , - 6 )$, radius $= 3$
D) center $( 6,5 )$, radius $= 9$

Question

Quizplus · Accepted Answer

The equation can be rewritten in the standard form $(x + 5)^2 + (y + 6)^2 = 3^2$, indicating the center is $(-5, -6)$ and the radius is 3.

Find the Center and the Radius of the Circle x2+y2+10x+12y+61=9x ^ { 2 } + y ^ { 2 } + 10 x + 12 y + 61 = 9x2+y2+10x+12y+61=9

Find the Center and the Radius of the Circle $x ^ { 2 } + y ^ { 2 } + 10 x + 12 y + 61 = 9$