Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$x^{2}+y^{2}=9$

A) center $\left( \frac { 3 } { 2 } , 0 \right)$; radius $= \frac { 3 } { 2 }$
B) center $\left( 0 , \frac { 3 } { 2 } \right) ;$ radius $= \frac { 3 } { 2 }$
C) center $( 0,0 )$; radius $= 3$
D) center $( 0,0 )$; radius $= \sqrt { 3 }$

Question

Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$x^{2}+y^{2}=9$

A) center $\left( \frac { 3 } { 2 } , 0 \right)$; radius $= \frac { 3 } { 2 }$ 
B) center $\left( 0 , \frac { 3 } { 2 } \right) ;$ radius $= \frac { 3 } { 2 }$ 
C) center $( 0,0 )$; radius $= 3$ 
D) center $( 0,0 )$; radius $= \sqrt { 3 }$

Quizplus · Accepted Answer

The Answer of Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$x^{2}+y^{2}=9$

A) center $\left( \frac { 3 } { 2 } , 0 \right)$; radius $= \frac { 3 } { 2 }$ 
B) center $\left( 0 , \frac { 3 } { 2 } \right) ;$ radius $= \frac { 3 } { 2 }$ 
C) center $( 0,0 )$; radius $= 3$ 
D) center $( 0,0 )$; radius $= \sqrt { 3 }$

Sketch the Graph of the Equation x2+y2=9x^{2}+y^{2}=9x2+y2=9 A) Center (32,0)\left( \frac { 3 } { 2 } , 0 \right)(23​,0)

Sketch the Graph of the Equation $x^{2}+y^{2}=9$ A) Center $\left( \frac { 3 } { 2 } , 0 \right)$