Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$(x+3)^{2}+(y+2)^{2}=4$

A) center $( - 3 , - 2 )$; radius $= 2$
B) center $( 3,2 )$; radius $= 2$
C) center $( 3 , - 2 )$; radius $= 2$
D) center $( - 3,2 )$; radius $= 2$

Question

Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$(x+3)^{2}+(y+2)^{2}=4$

A) center $( - 3 , - 2 )$; radius $= 2$ 
B) center $( 3,2 )$; radius $= 2$ 
C) center $( 3 , - 2 )$; radius $= 2$ 
D) center $( - 3,2 )$; radius $= 2$

Quizplus · Accepted Answer

The Answer of Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center and
radius.
-$(x+3)^{2}+(y+2)^{2}=4$

A) center $( - 3 , - 2 )$; radius $= 2$ 
B) center $( 3,2 )$; radius $= 2$ 
C) center $( 3 , - 2 )$; radius $= 2$ 
D) center $( - 3,2 )$; radius $= 2$

Sketch the Graph of the Equation (x+3)2+(y+2)2=4(x+3)^{2}+(y+2)^{2}=4(x+3)2+(y+2)2=4 A) Center (−3,−2)( - 3 , - 2 )(−3,−2)

Sketch the Graph of the Equation $(x+3)^{2}+(y+2)^{2}=4$ A) Center $( - 3 , - 2 )$