Find the center and the radius of the circle.
-$x ^ { 2 } + ( y - 8 ) ^ { 2 } = 64$
A) center $( 0 , - 8 )$; radius $= 8$
B) center $( 8,0 )$; radius $= 8$
C) center $( 0,8 )$; radius $= 8$
D) center $( 0,8 )$; radius $= 64$

Question

Quizplus · Accepted Answer

The equation of a circle in the standard form is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Comparing with the given equation $x^2 + (y - 8)^2 = 64$, we see that $h = 0$, $k = 8$, and $r^2 = 64$, which means $r = 8$. Therefore, the center is $(0, 8)$ and the radius is $8$.

Find the Center and the Radius of the Circle x2+(y−8)2=64x ^ { 2 } + ( y - 8 ) ^ { 2 } = 64x2+(y−8)2=64

Find the Center and the Radius of the Circle $x ^ { 2 } + ( y - 8 ) ^ { 2 } = 64$