Solve the problem.
-A certain noise has an intensity I of $4.01 \times 10 ^ { - 5 }$. Given that decibel level D is related to intensity by $\mathrm { D } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)$, where $\mathrm { I } _ { 0 }$ is $10 ^ { - 12 }$, determine the decibel level of the noise. Round your answer to the nearest decibel.
A) 175 decibels
B) 76 decibels
C) 8 decibels
D) 66 decibels

Question

Quizplus · Accepted Answer

To find the decibel level, substitute the given values into the formula: $D = 10 \log \left( \frac{4.01 \times 10^{-5}}{10^{-12}} \right)$. This simplifies to $D = 10 \log \left(4.01 \times 10^7\right)$, which rounds to approximately 76 decibels.

Solve the Problem 4.01×10−54.01 \times 10 ^ { - 5 }4.01×10−5

Solve the Problem $4.01 \times 10 ^ { - 5 }$