Solve the problem. Round your answer to the nearest tenth, when appropriate. Use the formula $$\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$$ as needed.
-Find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$if the $\mathrm { pH } = 5$.
A) $1.0 \times 10 ^ { 5 }$
B) $2.0 \times 10 ^ { 5 }$
C) $3.0 \times 10 ^ { - 5 }$
D) $1.0 \times 10 ^ { - 5 }$

Question

Quizplus · Accepted Answer

To find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$ when $\mathrm { pH } = 5$, we use the inverse of the given formula: $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] = 10^{-\mathrm { pH }}$. Substituting $5$ for $\mathrm { pH }$, we get $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] = 10^{-5}$, which is $1.0 \times 10^{-5}$.

Solve the Problem pH=−log⁡[H3O+]\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]pH=−log[H3​O+]

Solve the Problem $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$