Solve the Problem $\theta$ To the Horizontal with an Initial Speed $v _ { O }$

Solve the problem.
-The path of a projectile fired at an inclination $\theta$ to the horizontal with an initial speed $v _ { O }$ is a parabola. The range $\mathrm { R }$ of the projectile, the horizontal distance that the projectile travels, is found by the formula $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } }$ where $\mathrm { g } = 32.2$ feet per second per second or $\mathrm { g } = 9.8$ meters per second per second. Find the range of a projectile fired with an initial velocity of 144 feet per second at an angle of $35 ^ { \circ }$ to the horizontal. Round your answer to two decimal places.

A) $369.37 \mathrm { ft }$
B) $738.74 \mathrm { ft }$
C) $605.14 \mathrm { ft }$
D) $605.04 \mathrm { ft }$