Solve the problem.
-Ignoring friction, the time, $t$ (in seconds), required for a block to slide down an inclined plane is given by the formula $t = \sqrt { \frac { 2 b } { g \sin \theta \cos \theta } }$ where $b$ is the length of the base in feet and $g = 32.2$ feet per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with a base of 12 feet at an angle of $44 ^ { \circ }$ ? Round your answer to three decimal places.
A) $6.93 \mathrm { sec }$
B) $0.353 \mathrm { sec }$
C) $0.864 \mathrm { sec }$
D) $1.221 \mathrm { sec }$

Question

Quizplus · Accepted Answer

To find the time $t$, substitute $b = 12$, $g = 32.2$, and $\theta = 44^\circ$ into the formula: $t = \sqrt{\frac{2 \times 12}{32.2 \times \sin(44^\circ) \times \cos(44^\circ)}}$. Calculating this gives approximately $1.221$ seconds.

Solve the Problem ttt (In Seconds), Required for a Block to Slide Down an Required

Solve the Problem $t$ (In Seconds), Required for a Block to Slide Down an Required