Solve the problem.
-A projectile is fired with an initial velocity of 300 feet per second at an angle of $$70 ^ { \circ }$$ with the horizontal. In how many seconds will the projectile reach its maximum altitude? (Round your
Answer to the nearest tenth of a second.)
A) 5.4 sec
B) 13.6 sec
C) 16.9 sec
D) 8.8 sec

Question

Quizplus · Accepted Answer

The time to reach maximum altitude for a projectile is given by the formula $ t = \frac{v \sin(\theta)}{g} $, where $v$ is the initial velocity, $\theta$ is the launch angle, and $g$ is the acceleration due to gravity (approximately $32 \, \text{ft/s}^2$ for Earth). Plugging in the given values: $ t = \frac{300 \sin(70^\circ)}{32} \approx 8.8 $ seconds.

Solve the Problem 70∘70 ^ { \circ }70∘ With the Horizontal

Solve the Problem $70 ^ { \circ }$ With the Horizontal